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Also, assume that $A \\nabla_\\lambda B:=(1-\\lambda)A+\\lambda B$ and $A \\sharp_\\lambda B:=A^{\\frac{1}{2}}\\left(A^{-\\frac{1}{2}}BA^{-\\frac{1}{2}}\\right)^\\lambda A^{\\frac{1}{2}}$ are arithmetic and geometric means of $A, B$, respectively, where $0 < \\lambda < 1$. 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