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def

bpowSumTarget

definition
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module
IndisputableMonolith.Verification.YardstickAssignmentChoiceSet
domain
Verification
line
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plain-language theorem explainer

The structural sum target for the four sector B_pow exponents equals the active-edge count A, fixed at 1. Anyone imposing the yardstick sum filter on sector-to-value assignments cites this constant. The body is a one-line integer cast of A.

Claim. The target value of the sum of the four sector $B_{\mathrm{pow}}$ exponents is the active-edge count $A=1$, taken as an integer.

background

This module turns the O1 yardstick discussion into a finite combinatorial search: four candidate $B_{\mathrm{pow}}$ values and four candidate $r_0$ values are assigned to sectors by permutation, then filtered by structural constraints. Valid choice sets collapse to singletons under those filters.

The constant $A$ is the active-edge count per tick. In the foundation gap derivation it is defined as $A:=1$, and the mass-anchor layer records the same fact as active edges per tick equal to 1. Related identities include $\eta_B\cdot\Theta_{\mathrm{crit}}=\varphi^A=\varphi$.

Here the sum target is simply that integer $A$, so any assignment $(B_{\ell},B_{u},B_{d},B_{\mathrm{ew}})$ is required to satisfy $B_{\ell}+B_{u}+B_{d}+B_{\mathrm{ew}}=A$ when the structural sum filter is applied.

proof idea

One-line definition: cast the active-edge constant $A$ to $\mathbb{Z}$. No lemmas or tactics.

why it matters

The sum filter is the backbone of the Boolean structural constraints on $B_{\mathrm{pow}}$ assignments. Downstream theorems such as the anchor structural identities, the derivation of Boolean constraints from edge roles, and the equivalences that force the electroweak magnitude to equal $A$ all take the hypothesis that the four sector exponents sum to this target.

That filter is what collapses the enumerated choice set to the anchor assignment in the O1 progress narrative. In the broader Recognition picture the same $A=1$ enters the active-edge bookkeeping that ties $\varphi$-powers on the mass ladder to the eight-tick and gap structure; fixing the sum target at $A$ keeps the combinatorial search aligned with that bookkeeping.

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