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Let µ 1, µ 2 ∈ R, since M − ∪ j,kN k j → X − ∪ jNj is an 8 : 1 cover we have ∫ X α ∧ (µ 1β1 + µ 2β2) = 1 8 ∫ M − 2i(µ 1λ 1 − µ 2λ 2)dt ∧ dz1¯ 12¯ 23¯ 3 = 2(µ 1λ 1 − µ 2λ 2)

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math.DG 1

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2024 1

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UNVERDICTED 1

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