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SupposeE 1 ∈ pref(F)andE 2 ∈pref(F ⋆ 2 )butE=E 1 ∪E 2 /∈pref(F), then by the previous itemE∈adm(F), so there ex- ists a preferred supersetE ′ ⊋EofF

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cs.AI 1

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2026 1

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UNVERDICTED 1

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