For every poset P, the induced saturation function sat*([t]^n, P) is either eventually constant or Omega(sqrt(n)) as n grows, with chains constant and unique-twin-cover posets growing.
Linear Saturation for $\mathcal N$ via Butterflies
2 Pith papers cite this work. Polarity classification is still indexing.
abstract
Given a finite poset $\mathcal P$, how small can a family $\mathcal F$ of subsets of $[n]$ be such that $\mathcal F$ does not contain an induced copy of $\mathcal P$, but $\mathcal F\cup\{X\}$ contains such a copy for all $X\in\mathcal P([n])\setminus\mathcal F$? This is known as the induced saturation number of $\mathcal P$, denoted by $\text{sat}^*(n,\mathcal P)$. The main conjecture in the area is that the induced saturation number for any poset is either bounded, or linear. In this paper we establish linearity for the induced saturation number of the 4-point poset $\mathcal N$. Previously, it was known that $2\sqrt n\leq\text{sat}^*(n,\mathcal N)\leq 2n$. We show that $\text{sat}^*(n,\mathcal N)\geq\frac{n+6}{4}$. A crucial role in the proof is played by a structural feature of $\mathcal N$-saturated families, namely that if the family contains two antichains, one completely above the other, then it must also contain a `middle' point -- greater than one antichain and less than the other.
fields
math.CO 2years
2026 2verdicts
UNVERDICTED 2representative citing papers
The saturation number for the diamond poset is exactly n+1.
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Induced poset saturation in the hypergrid
For every poset P, the induced saturation function sat*([t]^n, P) is either eventually constant or Omega(sqrt(n)) as n grows, with chains constant and unique-twin-cover posets growing.
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The Exact Saturation Number for the Diamond
The saturation number for the diamond poset is exactly n+1.