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Lemma B.4 (Reflexivity).𝑀▷𝑀 Proof.Straightforward by induction on𝑀.β–‘ Lemma B.5 (Substitution).If 𝑀▷𝑀 β€² and 𝑁▷𝑁 β€² then 𝑀{π‘₯ := 𝑁}▷𝑀 β€²{π‘₯:=𝑁 β€²}

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