REVIEW 1 major objections 27 references
The Landau function and the Riemann Hypothesis
T0 review · 1 major / 0 minor · reviewed 2026-05-24 · grok-4.3
Pith's one-line read The inequality log g(n) < li^{-1}(n) for all positive integers n holds exactly when the Riemann hypothesis is true.
desk verdict The claimed equivalence cannot hold: the inequality is true for large n by standard asymptotics on g(n) and li^{-1}(n). read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
The Landau function g(n), the largest product of prime powers with sum of the terms at most n, together with its direct comparison against the inverse logarithmic integral li^{-1}(n).
What would settle it
An explicit integer n at which the computed value of log g(n) meets or exceeds li^{-1}(n) would violate the inequality and, by the claimed equivalence, falsify the Riemann hypothesis.
Extended reading notes
Core claim
The main result is that the property 'For all n > 0, log g(n) < li^{-1}(n)' (where g(n) is the maximal order of an element of the symmetric group of degree n) is equivalent to the Riemann hypothesis.
Load-bearing premise
The known asymptotic and extremal properties of the Landau function g(n), when combined with the definition of li^{-1}, produce an inequality whose validity is exactly coextensive with the Riemann hypothesis.
Editorial extensions
If this is right
- The Riemann hypothesis holds if and only if the inequality log g(n) < li^{-1}(n) is true for every positive integer n.
- Any counterexample n to the inequality would immediately disprove the Riemann hypothesis.
- Asymptotic and extremal results already known for g(n) translate directly into statements about the location of zeta zeros.
- The growth of the maximal orders in symmetric groups is governed by the same prime-distribution law that appears in the Riemann hypothesis.
Reading between the lines
- Direct computation of g(n) for successively larger n supplies a practical route to test the inequality numerically up to bounds where li^{-1}(n) can still be evaluated accurately.
- The equivalence supplies a new arithmetic-function formulation that could be compared with other known reformulations of the Riemann hypothesis for possible simplifications or contradictions.
- If the inequality holds up to a computable limit, it would confirm the hypothesis inside the corresponding range of zeta zeros, though this remains a finite check.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The manuscript claims that the property 'For all n > 0, log g(n) < li^{-1}(n)' (with g(n) the Landau function) is equivalent to the Riemann hypothesis.
Significance. If the claimed equivalence were valid, it would provide a novel characterization of the Riemann hypothesis in terms of the maximal order of elements in the symmetric group S_n.
major comments (1)
- [Abstract] Abstract: the claimed equivalence is incompatible with the known asymptotics log g(n) ∼ √(n log n) (Landau 1909) and li^{-1}(n) ∼ n log n; the inequality therefore holds unconditionally for all sufficiently large n, so the two sides cannot be coextensive.
Simulated Author's Rebuttal
We thank the referee for identifying a fundamental inconsistency between the claimed equivalence and the known asymptotics of the functions involved. We address the point directly below.
read point-by-point responses
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Referee: [Abstract] Abstract: the claimed equivalence is incompatible with the known asymptotics log g(n) ∼ √(n log n) (Landau 1909) and li^{-1}(n) ∼ n log n; the inequality therefore holds unconditionally for all sufficiently large n, so the two sides cannot be coextensive.
Authors: We agree with the referee. The asymptotic relations log g(n) ∼ √(n log n) and li^{-1}(n) ∼ n log n imply that log g(n) = o(li^{-1}(n)) as n → ∞, so the inequality log g(n) < li^{-1}(n) holds for all sufficiently large n independently of the Riemann hypothesis. The statement that the inequality holds for every n > 0 is therefore equivalent only to a finite verification up to some bound and cannot be coextensive with the Riemann hypothesis. This renders the main claim of the manuscript incorrect as stated. revision: yes
Circularity Check
No circularity: equivalence claim stated without self-referential construction or load-bearing self-citation in available text
full rationale
The abstract asserts that ∀n>0 log g(n) < li^{-1}(n) is equivalent to RH, but supplies no derivation chain, equations, or citations that reduce the claimed equivalence to a definition, fit, or prior self-result. No self-definitional steps, fitted inputs renamed as predictions, or ansatz smuggling appear. The derivation is treated as self-contained against external number-theoretic benchmarks (Landau function asymptotics, li inverse) until full text review shows otherwise. This is the default honest finding when no load-bearing reduction is exhibited.
Assumptions & free parameters
Cite this review
Pith. "Pith review of The Landau function and the Riemann Hypothesis." pith.science (2026). https://pith.science/paper/LLBV7PQS
@misc{pith2026190707664,
author = {Pith},
title = {Pith review of: The Landau function and the Riemann Hypothesis},
year = {2026},
howpublished = {\url{https://pith.science/paper/LLBV7PQS}},
note = {Machine review of arXiv:1907.07664}
}
abstract
The Landau function $g(n)$ is the maximal order of an element of the symmetric group of degree $n$; it is also the largest product of powers of primes whose sum is $\le n$. The main result of this article is that the property " For all $n > 0$ , $log g(n) < li^{-1} (n))$ " (where $li^{-1}(n)$ denotes the inverse function of the logarithmic integral) is equivalent to the Riemann hypothesis.
Figures
Reference graph
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Reviewed May 24, 2026 · model on record in the stance chip above.
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