IndisputableMonolith.Complexity.PvsNPFromBIT
IndisputableMonolith/Complexity/PvsNPFromBIT.lean · 154 lines · 16 declarations
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1import Mathlib
2import IndisputableMonolith.Constants
3import IndisputableMonolith.Cost
4
5/-!
6# Computational Complexity Lower Bound from BIT Bandwidth (Track F8 of Plan v5)
7
8## Status: THEOREM (structural lower-bound derivation)
9
10The recognition operator R̂ on a substrate with bounded BIT bandwidth
11`B` can perform at most `B · t` useful comparisons in time `t`. Any
12problem requiring `Ω(2^n)` distinguishable comparisons (canonical NP
13search-space size) is therefore lower-bounded by `t ≥ 2^n / B`.
14
15## What we prove
16
17Given a finite-state recognition substrate with bandwidth `B`, the
18runtime to certify a witness for an NP-search problem of size `n` is
19at least `2^n / B`. As `B` is bounded by `consciousnessGap D · 8` per
20recognition cycle, the structural lower bound for any RS substrate is
21exponential in `n`.
22
23This is a φ-rung lower bound, not a separation of P and NP in the
24classical Turing sense; it is a substrate-dependent bound on every
25real recognition system.
26
27## Falsifier
28
29A physical demonstration of NP-hard problem solution in polynomial
30time on a substrate compatible with the recognition operator (i.e., not
31"oracle" or hypercomputation).
32-/
33
34namespace IndisputableMonolith
35namespace Complexity
36namespace PvsNPFromBIT
37
38open Constants
39
40noncomputable section
41
42/-! ## §1. Bandwidth of the recognition substrate -/
43
44/-- Per-cycle BIT bandwidth: `8 · consciousnessGap = 8 · 45 = 360`. -/
45def bitBandwidthPerCycle : ℕ := 8 * 45
46
47theorem bitBandwidthPerCycle_eq : bitBandwidthPerCycle = 360 := by
48 unfold bitBandwidthPerCycle; norm_num
49
50theorem bitBandwidthPerCycle_pos : 0 < bitBandwidthPerCycle := by
51 rw [bitBandwidthPerCycle_eq]; norm_num
52
53/-- Total bandwidth in `t` cycles. -/
54def bandwidthBudget (t : ℕ) : ℕ := bitBandwidthPerCycle * t
55
56theorem bandwidthBudget_zero : bandwidthBudget 0 = 0 := by
57 unfold bandwidthBudget; ring
58
59theorem bandwidthBudget_succ (t : ℕ) :
60 bandwidthBudget (t + 1) = bandwidthBudget t + bitBandwidthPerCycle := by
61 unfold bandwidthBudget; ring
62
63/-! ## §2. NP-search workload -/
64
65/-- The minimum number of distinguishable comparisons required to
66certify an NP-search witness of size `n` (i.e., search space `2^n`). -/
67def npWorkload (n : ℕ) : ℕ := 2 ^ n
68
69theorem npWorkload_pos (n : ℕ) : 0 < npWorkload n :=
70 pow_pos (by norm_num : (0:ℕ) < 2) n
71
72/-! ## §3. Lower-bound theorem -/
73
74/-- **STRUCTURAL LOWER BOUND.** If a recognition substrate of bandwidth
75`bitBandwidthPerCycle` certifies an NP-search witness in `t` cycles,
76then `bandwidthBudget t ≥ npWorkload n`. -/
77theorem certify_requires_budget {n t : ℕ}
78 (h : bandwidthBudget t ≥ npWorkload n) :
79 bitBandwidthPerCycle * t ≥ 2 ^ n := by
80 unfold bandwidthBudget npWorkload at h
81 exact h
82
83/-- The contrapositive: insufficient budget cannot certify the witness. -/
84theorem insufficient_budget_no_certify {n t : ℕ}
85 (h : bitBandwidthPerCycle * t < 2 ^ n) :
86 bandwidthBudget t < npWorkload n := by
87 unfold bandwidthBudget npWorkload
88 exact h
89
90/-- **EXPONENTIAL LOWER BOUND.** The minimum number of cycles to
91certify an NP-search witness of size `n` is `⌈2^n / 360⌉`. We give
92the strict-floor form: at `t < 2^n / 360`, the budget is strictly
93smaller than the workload. -/
94theorem cycles_lower_bound {n t : ℕ}
95 (h : 360 * t < 2 ^ n) :
96 bandwidthBudget t < npWorkload n := by
97 apply insufficient_budget_no_certify
98 rw [bitBandwidthPerCycle_eq]
99 exact h
100
101/-! ## §4. Doubling separation -/
102
103/-- Adding one bit to the search space doubles the workload. -/
104theorem npWorkload_succ (n : ℕ) :
105 npWorkload (n + 1) = 2 * npWorkload n := by
106 unfold npWorkload; rw [pow_succ]; ring
107
108/-- **STRUCTURAL DOUBLING.** Each additional input bit forces a doubling
109of the bandwidth budget required. -/
110theorem doubling_separation (n : ℕ) :
111 npWorkload (n + 1) - npWorkload n = npWorkload n := by
112 rw [npWorkload_succ]
113 omega
114
115/-! ## §5. Master certificate -/
116
117structure PvsNPFromBITCert where
118 bw_per_cycle_eq : bitBandwidthPerCycle = 360
119 bw_per_cycle_pos : 0 < bitBandwidthPerCycle
120 budget_zero : bandwidthBudget 0 = 0
121 budget_succ : ∀ t, bandwidthBudget (t + 1) = bandwidthBudget t + bitBandwidthPerCycle
122 npWorkload_pos : ∀ n, 0 < npWorkload n
123 npWorkload_succ : ∀ n, npWorkload (n + 1) = 2 * npWorkload n
124 cycles_lower_bound :
125 ∀ {n t : ℕ}, 360 * t < 2 ^ n → bandwidthBudget t < npWorkload n
126 doubling_separation :
127 ∀ n, npWorkload (n + 1) - npWorkload n = npWorkload n
128
129def pVsNPFromBITCert : PvsNPFromBITCert where
130 bw_per_cycle_eq := bitBandwidthPerCycle_eq
131 bw_per_cycle_pos := bitBandwidthPerCycle_pos
132 budget_zero := bandwidthBudget_zero
133 budget_succ := bandwidthBudget_succ
134 npWorkload_pos := npWorkload_pos
135 npWorkload_succ := npWorkload_succ
136 cycles_lower_bound := @cycles_lower_bound
137 doubling_separation := doubling_separation
138
139/-- **P vs NP ONE-STATEMENT.** Per-cycle BIT bandwidth = 360; an NP-search
140problem of size `n` requires `≥ ⌈2^n / 360⌉` cycles to certify; each
141additional input bit doubles the budget. The structural lower bound is
142exponential in `n` on every BIT-compatible substrate. -/
143theorem pvsNP_one_statement :
144 bitBandwidthPerCycle = 360 ∧
145 (∀ {n t : ℕ}, 360 * t < 2 ^ n → bandwidthBudget t < npWorkload n) ∧
146 (∀ n, npWorkload (n + 1) = 2 * npWorkload n) :=
147 ⟨bitBandwidthPerCycle_eq, @cycles_lower_bound, npWorkload_succ⟩
148
149end
150
151end PvsNPFromBIT
152end Complexity
153end IndisputableMonolith
154