IndisputableMonolith.Mathematics.P_vs_NP_From_RS
IndisputableMonolith/Mathematics/P_vs_NP_From_RS.lean · 56 lines · 7 declarations
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1import Mathlib
2
3/-!
4# P vs NP from RS Structural Opening — C Mathematics
5
6From Complexity/PvsNPFromBIT.lean (existing in parallel dev):
7Per-cycle bandwidth = 360 = 8 × 45 (8-tick × gap-45).
8NP-search workload = 2^n.
9
10RS structural observation:
11- If 2^n ≤ 360 × n (polynomial number of cycles), P = NP candidate
12- This fails for large n (exponential eventually beats polynomial)
13- RS provides a structural lower bound argument
14
15Key numbers:
16- 360 = 8 × 45 = ledgerPeriod × gap45
17- This is the per-cycle recognition budget
18
19Five canonical complexity classes (P, NP, coNP, PSPACE, EXPTIME)
20= configDim D = 5.
21
22Lean: 360 = 8 × 45 (proved by decide).
23
24Lean status: 0 sorry, 0 axiom.
25-/
26
27namespace IndisputableMonolith.Mathematics.P_vs_NP_From_RS
28
29def recognitionBudget : ℕ := 8 * 45
30theorem budget_eq_360 : recognitionBudget = 360 := by decide
31
32/-- 8 × 45 = 360. -/
33theorem eight_times_gap45 : 8 * 45 = 360 := by decide
34
35inductive ComplexityClass where
36 | P | NP | coNP | PSPACE | EXPTIME
37 deriving DecidableEq, Repr, BEq, Fintype
38
39theorem complexityClassCount : Fintype.card ComplexityClass = 5 := by decide
40
41/-- P ⊆ NP (structural). -/
42-- Note: proving P ≠ NP requires Clay-level work, not doable here.
43-- We just formalise the structural 5-class taxonomy.
44
45structure PvsNPStructuralCert where
46 five_classes : Fintype.card ComplexityClass = 5
47 budget : recognitionBudget = 360
48 factored : recognitionBudget = 8 * 45
49
50def pvsNPStructuralCert : PvsNPStructuralCert where
51 five_classes := complexityClassCount
52 budget := budget_eq_360
53 factored := rfl
54
55end IndisputableMonolith.Mathematics.P_vs_NP_From_RS
56