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sat_recognition_time

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formal statement (Lean)

 245theorem sat_recognition_time (n : ℕ) (hn : 0 < n) :
 246    ∃ (c : ℝ), c > 0 ∧
 247    ∀ (decoder : Fin n → Bool → Prop),
 248      -- Any decoder that reads fewer than n bits cannot determine SAT result
 249      (∃ M : Finset (Fin n), M.card < n ∧
 250        ∀ result : Bool, ∃ tape1 tape2 : Fin n → Bool,
 251          (∀ i ∈ M, tape1 i = tape2 i) ∧
 252          decoder tape1 result ∧ ¬decoder tape2 result)
 253-/
 254
 255/-- **THE SEPARATION**: Tc << Tr (documentation / TODO)
 256
 257Intended claim: There is a gap between computation time (Tc) and recognition time (Tr).
 258For large n, Tc scales as O(n^{1/3} log n) while Tr scales as Ω(n). -/
 259/-!

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