REVIEW 1 major objections 4 minor 1 cited by
Effective resistance in planar graphs and continued fractions
T0 review · 1 major / 4 minor · reviewed 2026-08-07 · deepseek-v4-flash
Pith's one-line read This paper resolves the inverse problem for effective resistance in planar graphs: for every reduced fraction $c/t$ it constructs a simple planar graph with an edge of resistance $c/t$ using $O(\max(t/c,\, t/(t-c),\, \log t))$ vertices…
desk verdict Strong upper-bound construction, but the lower-bound proof in Proposition 1.2 has a real gap, so the 'up to constant' optimality claim is currently unproved. read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
The load-bearing object is the marked graph $(G,e)$ together with the spanning-tree ratio $\zeta(G,e) = \tau(G-e)/\tau(G/e)$, since deletion–contraction gives $\rho(G,e)=1/(1+\zeta(G,e))$. Three operations on marked graphs carry the argument: the marked sum $\oplus$, under which $\zeta$ values add; the plane dual, which inverts $\zeta$ (so $\rho$ maps to $1-\rho$); and the simplification operation (doubling every other edge, then subdividing every other edge), which makes a graph simple while preserving $\zeta$ at the cost of a factor of $4$ in edges. A continued-fraction construction provides, for any rational $q$, a planar marked graph with $\zeta(G,e)=q$ and edge count $S(q)+1$, where $S$ is the sum of the partial quotients. Bourgain's theorem supplies the arithmetic input: every rational in $[0,1)$ is a sum of rationals of small $S$-height, with total height $O(\log)$ of the denominator.
What would settle it
Compute, for unit fractions $1/t$ with large $t$, the minimum total $S$-height of an expression $1/t = q_1+\cdots+q_k$ with each $q_i \in \mathbb{Q}\cap(-1,1)$; if this minimum grows faster than $C\log t$, then the construction of Theorem 1.1 collapses because the $\log t$ term in (1.3) would be too small. Graph-theoretically, enumerate simple planar graphs up to $n$ vertices, compute all achievable edge resistances, and check whether a planar graph with resistance $1/t$ appears for $n = o(t)$; Proposition 1.2 forbids $n \le C' t$, so any such graph would falsify the lower bound.
Extended reading notes
Core claim
The paper's central claim is Theorem 1.1: for every coprime pair $t > c \ge 1$ there exists a simple planar graph $G=(V,E)$ and an edge $e$ with $\rho(G,e) = \tau(G/e)/\tau(G) = c/t$ and $|V| \le C\max(t/c,\, t/(t-c),\, \log t)$ for a universal constant $C$. Proposition 1.2 gives the matching lower bound $|V| \ge C'\max(t/c,\, t/(t-c),\, \log t)$ for any simple planar graph realizing a reduced resistance $c/t$ on a non-bridge edge. Together these resolve the inverse problem for planar effective resistance up to a universal constant. The paper also notes the corollary that for every integer $t\ge 2$ there is a simple connected planar graph with $\tau(G)\equiv 0 \pmod t$ and $O(\log t)$ vertices.
Load-bearing premise
The upper bound relies on Bourgain's theorem that every rational $d/c$ in $[0,1)$ can be written as a sum of rationals each of small continued-fraction height, with the total height growing only logarithmically in $c+d$.
Editorial extensions
If this is right
- For every reduced resistance $c/t$ there is a simple planar graph with that resistance on $O(\max(t/c,\, t/(t-c),\, \log t))$ vertices, and no such graph can be substantially smaller.
- The extremal size is governed by the reciprocal of the resistance, the reciprocal of its complement, and the logarithm of the denominator, with the planar-dual symmetry $\rho \leftrightarrow 1-\rho$ reflected in the symmetric term $t/(t-c)$.
- For every integer $t\ge 2$ there exists a simple connected planar graph with $\tau(G)\equiv 0 \pmod t$ and only $O(\log t)$ vertices.
- The result extends earlier bounds that required the resistance to lie in $[1/3,2/3]$ and allowed multiple edges, to all rational resistances with simple graphs.
- The construction is effective in principle: given $c/t$, one can assemble the graph from continued-fraction data once Bourgain's decomposition is supplied.
Reading between the lines
- The same marked-sum and simplification machinery should transfer to other invariants expressible as ratios of spanning-tree counts under deletion and contraction, such as other Tutte-polynomial evaluations.
- The result suggests a concrete algorithmic challenge: make Bourgain's decomposition constructive, turning the existence proof into a polynomial-time procedure that outputs the $O(\log t)$-vertex planar graph realizing a given rational resistance.
- The exact form of the extremal bound invites a sharper conjecture: that the true minimal vertex count, before universal constants, is governed by the continued-fraction expansion of $c/t$ itself, not merely by the three-way maximum.
- A direct comparison with the poset analogue from the authors' related work suggests that the logarithmic term may be removable in that setting too, since the obstruction there is a technical limitation of the flip-flop construction rather than the arithmetic growth.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper studies the inverse problem for effective resistance in planar graphs. For a reduced fraction c/t, Theorem 1.1 constructs a simple planar graph G with an edge e such that ρ(G,e)=c/t and |V| ≤ C max(t/c, t/(t−c), log t), and Proposition 1.2 claims a matching lower bound |V| ≥ C′ max(t/c, t/(t−c), log t). The upper-bound construction (Theorem 1.5) represents the target ratio as a sum of rationals via Bourgain's continued-fraction theorem, builds marked graphs for each summand, and combines them by a marked-sum operation followed by a new simplification operation that preserves the spanning-tree ratio. The lower bound uses commute-time inequalities, planar duality, and Euler's formula.
Significance. If correct, the paper resolves the planar inverse effective-resistance problem up to universal constants, identifying the extremal size as max(1/ρ, 1/(1−ρ), log t). The construction is explicit and parameter-free, and the simplification operation (Lemma 2.4) is a clean technical contribution. The upper-bound proof is modular and easy to verify. However, the proof of the matching lower bound contains a genuine gap, so the optimality claim is not currently established.
major comments (1)
- [§3.3, Eq. (3.7)] The proof of the second inequality in Proposition 1.2 applies Lemma 3.4 and then the first inequality (3.6) to the plane dual G*. Inequality (3.6) relies on the graph being simple, since it uses deg(x), deg(y) < |V|. The dual of a simple planar graph need not be simple; for example, for G = C_n, G* has two vertices and n parallel edges, so deg(f) = n = |F|, and the analogue of (3.6) for G* would assert 2 > n, which is false. Indeed the displayed chain |V| > |F|/2 > 1/(2ρ(G*,e)) fails for n > 2 because 1 < n/2. Thus the lower bound |V| ≥ C′ t/(t−c) is not established as written. Since Proposition 1.2 is the matching lower bound that shows the upper bound is optimal up to a constant, this is a load-bearing gap. The proof must either give a direct argument for the second bound that does not require G* to be simple, or demonstrate that the failure of simplicity (multiple edges and loops) does not invalidate the estimate.
minor comments (4)
- [§3.3 (Lemma 3.3)] There is a typographical error in Lemma 3.3: 'simple planar marked graph (G, E)' should be '(G, e)', and the formula for |E∘| is printed as '4(|E|−1)+1' but appears as '4|E|−1)+1' in the text.
- [§3.2 (Lemma 3.2)] The phrase 'Theorem 1.5 applied to q1 ← (d/c−d′/c′) and k=1' is informal; the substitution should be written explicitly for clarity.
- [§3.3 (Proposition 1.2)] The third inequality uses t ≤ τ(G); this follows from the reduced form of c/t and the integrality of τ(G/e), but the justification is omitted and should be stated.
- [§4.3] The remark that the constant 1/2 in (3.7) can be removed should be revisited after the simplicity issue with the dual is resolved; as written, the main obstacle is not the constant but the validity of the inequality.
Circularity Check
No circularity found: the main construction and lower bounds use external theorems and prior results that do not assume the target ratio.
full rationale
The paper's derivation is not circular. Theorem 1.1 is obtained by combining Bourgain's external Theorem 1.4 with Theorem 1.5, whose proof uses Proposition 2.1 and Lemma 2.2 cited from the authors' prior papers. These cited lemmas are constructive statements about continued fractions and marked graph sums; they do not assume Theorem 1.1 or the specific target resistance c/t. The simplification operation in Section 2.5 is proved in this paper via explicit spanning-tree counting and plane duality (Lemma 2.4), so the simplicity of the final graph is not imported by assumption. The lower bound Proposition 1.2 uses standard random-walk/commute-time inequalities and Euler's formula, not fitted parameters, and the target fraction c/t enters only as the input to the estimates. No fitted quantity is later renamed as a prediction, and no uniqueness theorem or ansatz is imported from the authors' own work to force the construction. The possible gap in applying Lemma 3.4 to the possibly non-simple dual graph in inequality (3.7) is a correctness concern, not a circularity concern.
Assumptions & free parameters
assumptions (5)
- domain assumption Bourgain's decomposition theorem [Bou12, Prop. 1]: every rational d/c in [0,1) equals q_1+...+q_k with q_i in Q∩(-1,1) and Σ S(|q_i|) ≤ C log(c+d).
- domain assumption Proposition 2.1 from [CP24c, Thm 5.1]: for any rational d/c with continued fraction [a0; a1,...,aℓ], there exists a planar marked graph G with τ(G-e)=d, τ(G/e)=c and |E|=a0+...+aℓ+1.
- domain assumption Lemma 2.2 (marked sum additivity): for proper marked graphs, ζ(G⊕G',e) = ζ(G,e) + ζ(G',e).
- domain assumption Lemma 3.4 (commute time bound): ρ(G,e) ≥ 1/2(1/deg(x)+1/deg(y)), derived from κ(G,e)=2|E|ρ ≥ |E|(1/deg(x)+1/deg(y)).
- standard math Euler's formula for simple planar graphs (|E| ≤ 3|V|-6, |F| ≤ 2|V|-4) and the exponential bound τ(G) < 2^{|E|} for the number of spanning trees.
Cite this review
Pith. "Pith review of Effective resistance in planar graphs and continued fractions." pith.science (2026). https://pith.science/paper/RROFD57K
@misc{pith2026250519168,
author = {Pith},
title = {Pith review of: Effective resistance in planar graphs and continued fractions},
year = {2026},
howpublished = {\url{https://pith.science/paper/RROFD57K}},
note = {Machine review of arXiv:2505.19168}
}
abstract
For a simple graph $G=(V,E)$ and edge $e\in E$, the effective resistance is defined as a ratio $\frac{\tau(G/e)}{\tau(G)}$, where $\tau(G)$ denotes the number of spanning trees in $G$. We resolve the inverse problem for the effective resistance for planar graphs. Namely, we determine (up to a constant) the smallest size of a simple planar graph with a given effective resistance. The results are motivated and closely related to our previous work arXiv:2411.18782 on Sedl\'a\v{c}ek's inverse problem for the number of spanning trees.
Forward citations
Cited by 1 Pith paper
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On some results of Korobov and Larcher and Zaremba's conjecture
Zaremba's conjecture holds for all large primes: an absolute M exists so every large prime p admits a coprime a whose continued-fraction partial quotients are all ≤ M, with quantitative lower bounds on the number of such a.
Reference graph
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Reviewed August 7, 2026 · model on record in the stance chip above.
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