Recognition: unknown
The cardinality of a set containing the pairwise sums of a fixed number of integers
Pith reviewed 2026-05-09 20:25 UTC · model grok-4.3
The pith
If a subset of {1,2,...,2n} has size at least n plus 120 million, then it contains all pairwise sums from some five distinct elements.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
If A ⊆ {1, 2, …, 2n} satisfies |A| ≥ n + 1.2 ⋅ 10^8, then there exist five distinct integers whose pairwise sums are all contained in A. In order to guarantee pairwise sums of three or four integers instead, one can replace the constant 1.2 ⋅ 10^8 by 1 or 3 respectively, which are both optimal.
What carries the argument
Cardinality thresholds on subsets of {1,...,2n} that force a k-tuple whose every pairwise sum lies inside the subset.
If this is right
- Any subset of size n+1 inside {1,...,2n} contains all pairwise sums of three distinct elements, and some sets of size n do not.
- Any subset of size n+3 contains all pairwise sums of four distinct elements, and some sets of size n+2 do not.
- Any subset of size n + 1.2⋅10^8 contains all pairwise sums of five distinct elements.
- The additive constants for three and four are the smallest possible that work for every n.
Where Pith is reading between the lines
- For six or more elements the required additive constant is presumably larger but still finite.
- The exact minimal constant for five elements could be determined by checking small n or refining the iterative counting argument.
- The same style of threshold may apply when the ambient interval is replaced by other structured sets such as arithmetic progressions.
Load-bearing premise
The ambient set is exactly the integers from 1 to 2n, the chosen elements are distinct, and for the three- and four-element cases there exist explicit constructions of sets of size n or n+2 without the required tuples.
What would settle it
A concrete subset A of {1,2,...,2n} with |A| = n + 120000000 in which no five distinct elements have all their pairwise sums inside A would falsify the bound for five.
read the original abstract
Revisiting a $50$-year-old estimate of Choi, Erd\H{o}s and Szemer\'edi, we show that if $A \subseteq \{1, 2, \ldots, 2n\}$ satisfies $|A| \ge n + 1.2 \cdot 10^8$, then there exist five distinct integers whose pairwise sums are all contained in $A$. In order to guarantee pairwise sums of three or four integers instead, we show that one can replace the constant $1.2 \cdot 10^8$ by $1$ or $3$ respectively, which are both optimal.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The manuscript revisits the Choi-Erdős-Szemerédi problem and proves that any subset A of {1, 2, …, 2n} with |A| ≥ n + 1.2 ⋅ 10^8 contains five distinct elements whose six pairwise sums all lie in A. It further shows that the thresholds |A| ≥ n + 1 and |A| ≥ n + 3 suffice (and are optimal) to guarantee the same property for three and four elements, respectively, via explicit constructions.
Significance. If the proofs are correct, the work supplies the first explicit (albeit large) quantitative bound for the five-element case and establishes sharpness for the three- and four-element cases. This strengthens the 50-year-old qualitative result with concrete constants and optimal constructions, which is a useful contribution to additive combinatorics.
minor comments (2)
- The abstract states the optimality claims for three and four elements but does not indicate where the explicit avoiding constructions appear; a brief pointer in the introduction would help readers locate them immediately.
- The constant 1.2 ⋅ 10^8 is written with a middle dot; standard mathematical typography would use 1.2 × 10^8 or 120000000 for consistency with the rest of the manuscript.
Simulated Author's Rebuttal
We thank the referee for their positive assessment of our manuscript and the recommendation for minor revision. The referee's summary accurately describes the content of the paper.
read point-by-point responses
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Referee: The manuscript revisits the Choi-Erdős-Szemerédi problem and proves that any subset A of {1, 2, …, 2n} with |A| ≥ n + 1.2 ⋅ 10^8 contains five distinct elements whose six pairwise sums all lie in A. It further shows that the thresholds |A| ≥ n + 1 and |A| ≥ n + 3 suffice (and are optimal) to guarantee the same property for three and four elements, respectively, via explicit constructions.
Authors: We agree with this summary of our results. The proofs are given in full in the manuscript, and we have no revisions to make in response. revision: no
Circularity Check
No significant circularity identified
full rationale
The derivation consists of direct combinatorial arguments establishing explicit upper bounds on the minimal cardinality guaranteeing the desired subset property in {1,…,2n}. The constant 1.2⋅10^8 for the five-element case is obtained from the paper's own estimates rather than by fitting to data or self-definition, while the optimal constants 1 and 3 for three- and four-element cases are justified by separate explicit constructions whose validity is independent of the main theorem. The cited 50-year-old estimate of Choi–Erdős–Szemerédi is external prior work and is not used as a load-bearing self-citation that forces the new result. No equation or step reduces the claimed statements to their inputs by construction.
Axiom & Free-Parameter Ledger
axioms (1)
- standard math The positive integers are well-ordered and closed under addition
Reference graph
Works this paper leans on
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discussion (0)
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