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Weak Minimizing Property and the Compact Perturbation Property for the Minimum Modulus
Pith reviewed 2026-05-10 15:18 UTC · model grok-4.3
The pith
The pair (c₀, c₀) fails the compact perturbation property for the minimum modulus.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
We give a negative answer to this question by proving that (c₀, c₀) does not have the CPPm. The proof is constructive, exhibiting a non-min-attaining operator whose minimum modulus is strictly increased by a rank-one compact perturbation. Moreover, if X=𝕂⊕_∞Y with Y non-reflexive, then the pair (X,X) fails the CPPm.
What carries the argument
The explicit construction of a non-min-attaining operator T on c₀ (or on X=𝕂⊕_∞Y) such that there exists a rank-one compact K with m(T+K) > m(T).
If this is right
- (c₀, c₀) fails the CPPm.
- If X = 𝕂 ⊕_∞ Y with Y non-reflexive, then (X, X) fails the CPPm.
- The failure is tied to the non-reflexivity of the underlying space and the explicit sequence-space construction.
Where Pith is reading between the lines
- Analogous failures of the CPPm may hold in other non-reflexive Banach spaces that lack the direct-sum structure used here.
- The same constructive approach could be tested on related perturbation properties for operators between different sequence spaces.
Load-bearing premise
There exists a specific non-min-attaining operator on c₀ whose minimum modulus increases under some rank-one compact perturbation, due to the sequence-space properties of c₀.
What would settle it
Direct verification on the constructed operator that m(T+K) equals m(T) for the given rank-one compact K, or that no compact perturbation increases m(T) for any non-attaining T on c₀.
read the original abstract
For an operator $T:X\to Y$, denote $m(T)=\inf\{\|Tx\|:x\in S_X\}$. A sequence $(x_n)$ in $S_X$ is said to be minimizing for $T$ if $\|Tx_n\|\to m(T)$. The weak minimizing property (WmP), introduced by Chakraborty, requires that every operator admitting a non-weakly null minimizing sequence attains its minimum modulus. More recently, Han~\cite{Han2026} introduced the Compact Perturbation Property for the minimum modulus (CPPm), which requires that for every operator $T:X\to Y$ that does not attain its minimum modulus, \[ \sup_{K\in\mathcal{K}(X,Y)} m(T+K)=m(T). \] In~\cite{Han2026}, it is shown that $(\ell_1,\ell_1)$ fails both properties, while $(c_0,c_0)$ fails the WmP. However, whether $(c_0,c_0)$ has the CPPm was left open (Problem~3.6). In this paper, we give a negative answer to this question by proving that $(c_0,c_0)$ does not have the CPPm. The proof is constructive, exhibiting a non-min-attaining operator whose minimum modulus is strictly increased by a rank-one compact perturbation. Moreover, we show that this phenomenon is not specific to $c_0$: if $X=\mathbb{K}\oplus_\infty Y$ with $Y$ non-reflexive, then the pair $(X,X)$ fails the CPPm.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The manuscript proves that the pair (c₀, c₀) fails the Compact Perturbation Property for the minimum modulus (CPPm). It does so via an explicit construction of a non-minimum-attaining operator T : c₀ → c₀ for which there exists a rank-one compact K with m(T+K) > m(T). The authors further show that if X = 𝕂 ⊕_∞ Y with Y non-reflexive, then the pair (X, X) likewise fails CPPm. This supplies a negative answer to the open Problem 3.6 of Han (2026).
Significance. The result is significant because it resolves an open question with a concrete, constructive counterexample rather than a non-constructive existence argument. The use of standard sequence-space techniques on c₀ and the exploitation of non-reflexivity in the direct-sum generalization provide clear, falsifiable insight into when CPPm fails. This strengthens the literature on minimum-modulus properties by distinguishing the behavior of CPPm from the already-known failure of the weak minimizing property on the same pair.
minor comments (2)
- [Main construction section] In the statement of the main theorem (presumably Theorem 3.1 or its equivalent), the explicit sequences or basis vectors used to define T and the rank-one perturbation K should be written with full index ranges to facilitate direct verification of the inequality m(T+K) > m(T).
- [Generalization paragraph] The generalization to X = 𝕂 ⊕_∞ Y would benefit from a short remark clarifying whether the same rank-one form of K works verbatim or requires a minor adjustment when Y is an arbitrary non-reflexive space.
Simulated Author's Rebuttal
We thank the referee for the positive assessment of our manuscript, the recognition of its significance in providing a constructive counterexample to the open Problem 3.6, and the recommendation for minor revision. No major comments were raised in the report.
Circularity Check
No significant circularity; constructive counterexample is self-contained
full rationale
The paper resolves the open Problem 3.6 from Han2026 by exhibiting an explicit non-min-attaining operator T on c0 (and its generalization to X = K ⊕_∞ Y) together with a rank-one compact K such that m(T+K) > m(T). This is a direct, parameter-free construction relying on sequence-space properties of c0 and non-reflexivity of Y; no equation reduces to a prior fitted quantity, no ansatz is smuggled via self-citation, and the citation to Han2026 serves only to state the open question rather than to justify the proof. The derivation chain is therefore independent of its inputs and receives the default non-circularity finding.
Axiom & Free-Parameter Ledger
axioms (2)
- domain assumption c₀ is a non-reflexive Banach space with the standard Schauder basis and known dual properties.
- domain assumption Existence of non-min-attaining operators on c₀ with non-weakly-null minimizing sequences.
Reference graph
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