A note on cycles in cyclically 4-edge-connected cubic planar graphs
Pith reviewed 2026-05-12 01:15 UTC · model grok-4.3
The pith
If a graph H formed by deleting two adjacent vertices from a cyclically 4-edge-connected cubic planar graph has circumference at least k, then it contains a cycle whose length is between k and 3k/2.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
Let H be obtained from a cyclically 4-edge-connected cubic planar graph Y other than K4 by deleting two adjacent vertices. If H has circumference at least k for some even integer k ≥ 4, then H contains a cycle of length between k and 3k/2. The proof combines Euler's formula and the Three Edge Lemma. As a consequence, the line graph G of Y contains a cycle of length l avoiding any prescribed vertex of G, for every l in {3} ∪ {5, …, |V(G)| − 1}.
What carries the argument
The deletion of two adjacent vertices from Y to produce H, which preserves enough structure for Euler's formula and the Three Edge Lemma to force an intermediate-length cycle when the circumference is at least k.
If this is right
- The line graph G of Y admits a cycle of every allowed length l that misses any chosen vertex.
- The cycle spectrum of the line graph covers all integers from 3 to |V(G)| except possibly 4.
- The same length bound applies uniformly for every even k that is at most the circumference of H.
Where Pith is reading between the lines
- The technique of vertex deletion plus Euler's formula might be adapted to study cycle lengths in graphs obtained by other small modifications of planar cubic graphs.
- Verification on small examples such as the prism graphs or the dodecahedron could reveal whether the 3k/2 bound is sharp.
- If the bound holds, it supplies a concrete step toward determining the full set of avoidable cycle lengths in line graphs of 4-edge-connected planar graphs.
Load-bearing premise
Y must be cyclically 4-edge-connected and cubic planar but not K4, with H formed precisely by deleting two adjacent vertices.
What would settle it
A cyclically 4-edge-connected cubic planar graph Y other than K4 such that after deleting two adjacent vertices the resulting H has circumference k yet contains no cycle whose length lies strictly between k and 3k/2.
read the original abstract
Let $H$ be obtained from a cyclically $4$-edge-connected cubic planar graph $Y$ other than $K_4$ by deleting two adjacent vertices. We provide a short proof that if $H$ has circumference at least $k$ for some even integer $k \ge 4$, then $H$ contains a cycle of length between $k$ and $3k/2$. As a consequence, we show that the line graph $G$ of $Y$ contains a cycle of length $l$ avoiding any prescribed vertex of $G$, for every $l \in \{3\} \cup \{5, \dots, |V(G)| - 1\}$. The proofs integrate Euler's formula and the Three Edge Lemma, established by Thomas and Yu, and independently by Sanders, in a novel way. This work was partially motivated by conjectures of Bondy and Malkevitch.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The manuscript claims that if H is obtained by deleting two adjacent vertices from a cyclically 4-edge-connected cubic planar graph Y other than K4, and if the circumference of H is at least k for some even integer k ≥ 4, then H contains a cycle of length l with k ≤ l ≤ 3k/2. As a consequence, the line graph G of Y contains a cycle of length l avoiding any prescribed vertex of G, for every l in {3} ∪ {5, …, |V(G)|−1}. The proofs combine Euler's formula with the Three Edge Lemma of Thomas-Yu and Sanders.
Significance. If correct, the result supplies a concrete interval guarantee on cycle lengths in the graphs H, which immediately yields a near-complete cycle spectrum (avoiding one vertex) in the line graphs of the original cubic planar graphs. The short, self-contained argument that integrates two standard tools without introducing free parameters or ad-hoc constructions is a clear strength and directly addresses aspects of the Bondy-Malkevitch conjectures mentioned in the abstract.
minor comments (2)
- [Proof of Theorem 1] The precise statement of the Three Edge Lemma (including its hypotheses on the graph class) is not recalled in the manuscript; adding a one-sentence restatement before its first use would improve readability for readers who do not have the reference at hand.
- [Corollary 2] In the consequence for line graphs, the range begins at 3 and then jumps to 5; a brief sentence explaining why length 4 is excluded (or confirming it is impossible under the hypotheses) would clarify the result.
Simulated Author's Rebuttal
We thank the referee for their careful summary of the manuscript, the positive assessment of its significance, and the recommendation for minor revision. No specific major comments were raised in the report.
Circularity Check
No significant circularity
full rationale
The paper delivers a short proof that if the graph H (obtained by deleting two adjacent vertices from a cyclically 4-edge-connected cubic planar graph Y ≠ K4) has circumference at least k (even k ≥ 4), then H contains a cycle of length between k and 3k/2. This is established by combining Euler's formula with the Three Edge Lemma (Thomas-Yu and Sanders, external citations with no author overlap). The consequence for line graphs of Y follows directly. No step reduces by construction to a fitted parameter, self-definition, or self-citation chain; the derivation is self-contained against standard planar-graph tools and independent lemmas.
Axiom & Free-Parameter Ledger
axioms (2)
- standard math Euler's formula V - E + F = 2 for connected planar graphs
- domain assumption Three Edge Lemma (Thomas-Yu and Sanders)
Lean theorems connected to this paper
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IndisputableMonolith/Foundation/AlexanderDuality.leanalexander_duality_circle_linking unclear?
unclearRelation between the paper passage and the cited Recognition theorem.
Let H be obtained from a cyclically 4-edge-connected cubic planar graph Y other than K4 by deleting two adjacent vertices. ... if H has circumference at least k ... then H contains a cycle of length between k and 3k/2.
What do these tags mean?
- matches
- The paper's claim is directly supported by a theorem in the formal canon.
- supports
- The theorem supports part of the paper's argument, but the paper may add assumptions or extra steps.
- extends
- The paper goes beyond the formal theorem; the theorem is a base layer rather than the whole result.
- uses
- The paper appears to rely on the theorem as machinery.
- contradicts
- The paper's claim conflicts with a theorem or certificate in the canon.
- unclear
- Pith found a possible connection, but the passage is too broad, indirect, or ambiguous to say the theorem truly supports the claim.
Reference graph
Works this paper leans on
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discussion (0)
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