pith. sign in

arxiv: 1703.00341 · v3 · pith:OE7KDZYJnew · submitted 2017-03-01 · 🧮 math.DG

Geometry of Asymptotically harmonic manifolds with minimal horospheres

classification 🧮 math.DG
keywords manifoldharmonicmanifoldsflathorospheresminimalorderthen
0
0 comments X
read the original abstract

$(M^n,g)$ be a complete Riemannian manifold without conjugate points. In this paper, we show that if $M$ is also simply connected, then $M$ is flat, provided that $M$ is also asymptotically harmonic manifold with minimal horospheres (AHM). The (first order) flatness of $M$ is shown by using the strongest criterion: $\{{e_i}\}$ be an orthonormal basis of $T_{p}M$ and $\{b_{e_{i}}\}$ be the corresponding Busemann functions on $M$. Then, (1) The vector space $V = span\{b_{v} | v \in T_{p}M \}$ is finite dimensional and dim $V = $ dim $M = n$.(2) $\{\nabla b_{e_i}(p) \}$ is a global parallel orthonormal basis of $T_{p}M$ for any $p \in M$. Thus, $M$ is a parallizable manifold. And (3) F : M -> R^n defined by $F(x) = (b_{e_1}(x), b_{e_{2}}(x), \cdots, b_{e_{n}}(x)),$ is an isometry and therefore, $M$ is flat. Consequently, AH manifolds can have either polynomial or exponential volume growth,generalizing the corresponding result of [18] for harmonic manifolds. In case of harmonic manifold with minimal horospheres (HM), the (second order) flatness was proved in [23] by showing that $span\{b_{v}^2 | v \in T_{p}M \}$ is finite dimensional. We conclude that, the results obtained in this paper are the strongest and wider in comparison to harmonic manifolds, which are known to be AH. In fact, our proof shows the more generalized result, viz.: If (M,g) is a non-compact, complete, connected Riemannian manifold of infinite injectivity radius and of subexponential volume growth, then M is a first order flat manifold.

This paper has not been read by Pith yet.

discussion (0)

Sign in with ORCID, Apple, or X to comment. Anyone can read and Pith papers without signing in.