While the supplied Recognition Science source does not contain a declaration named precisely normalized_implies_G_zero, the exact mathematical concept is formalized in the module under the name G_zero_of_unit. Here is the breakdown of that theorem:
1. What the Declaration Says in Plain English
If a candidate cost function $F$ assigns zero cost to an input of $1$ (i.e., $F(1) = 0$), then its log-coordinate reparametrization $G(t) = F(e^t)$ evaluates to zero at $t = 0$.
2. Why it Matters in Recognition Science
In Recognition Science, the central J-cost function quantifies the "ledger cost" of recognizing a spatial scaling factor $r$. A definitional MODEL constraint is that the identity scale ($r = 1$) incurs zero cost, as nothing changes.
To prove the uniqueness of the J-cost function (Theorem T5 in the RS forcing chain), the mathematics shifts from multiplicative scale factors $r > 0$ to additive log-coordinates $t = \ln(r)$. The function G represents this shift. G_zero_of_unit translates the physical "identity costs nothing" boundary condition into the standard mathematical initial condition $G(0) = 0$. This is a required step to solve the ensuing d'Alembert equations that force the unique cost formula.
3. How to Read the Formal Statement
lemma G_zero_of_unit (F : ℝ → ℝ) (hUnit : F 1 = 0) : G F 0 = 0
F : ℝ → ℝintroduces a generic real-valued function (the candidate cost function).hUnit : F 1 = 0is the hypothesis (namedhUnit) that evaluating $F$ at $1$ yields $0$. This is the normalization condition.G F 0 = 0is the conclusion.G Fis the log-reparametrized function. Evaluated at $0$, it must yield $0$.
4. Visible Dependencies
The theorem depends purely on the definitional model G, defined as G F t = F (Real.exp t). The proof in Lean (simpa [G] using hUnit) is a one-line substitution reflecting that $e^0 = 1$, making $G(0) = F(e^0) = F(1) = 0$.
5. What this Declaration Does Not Prove
This lemma is merely a coordinate-translation helper. It does not prove the uniqueness of the J-cost function (T5, t5_holds), nor does it prove that $F$ is smooth, reciprocal-symmetric, or equal to the hyperbolic cosine. It strictly isolates the trivial arithmetic shift of the boundary condition.