theorem
proved
lambda_rec_is_forced
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IndisputableMonolith.Constants.LambdaRecDerivation on GitHub at line 114.
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111 · intro h
112 rw [h]; ring
113
114theorem lambda_rec_is_forced :
115 ∃! lambda : ℝ, lambda > 0 ∧ K lambda = 0 := by
116 use lambda_rec
117 constructor
118 · exact ⟨lambda_rec_pos, lambda_rec_is_root⟩
119 · intro y ⟨hy_pos, hy_root⟩
120 exact (lambda_rec_unique_root y hy_pos).mp hy_root
121
122/-! ## The Complete G Derivation Chain (Q1 Answer)
123
124This section closes the full chain from Q3 cube geometry to κ = 8φ⁵:
125
1261. The Q₃ cube has 8 vertices, 12 edges, 6 faces (from DimensionForcing)
1272. Curvature quanta |κ| = 4 are distributed over 8 faces of S² bounding
128 each vertex of Q₃, with Gauss-Bonnet normalization χ(S²) = 2
1293. Balance condition: J_bit = J_curv forces λ_rec = 1/√2 (lambda_0)
1304. In RS-native units where ℓ₀ = 1, λ_rec = ℓ₀ = 1 (the discrete
131 lattice sets the scale, absorbing the √2 into the unit convention)
1325. G = λ_rec² c³ / (π ℏ) with c = 1, ℏ = φ⁻⁵ gives G = φ⁵/π
1336. κ = 8πG/c⁴ = 8π(φ⁵/π)/1 = 8φ⁵
134
135The curvature packet derivation:
136- Q₃ has 6 faces; each face subtends a dihedral angle of π/2
137- The total curvature deficit at each vertex: 2π − 3(π/2) = π/2
138- For 8 vertices: total curvature = 8 × (π/2) = 4π = 2π × χ(S²)
139- The curvature per unit solid angle normalized by Gauss-Bonnet:
140 |κ_normalized| = total_curvature / (4π) = 1
141- Distributing over bounding area 4πλ²: J_curv = 2λ² -/
142
143/-- Q₃ cube vertex count. -/
144def Q3_vertices : ℕ := 8