The sharp threshold for Hausdorff convexification under Minkowski addition
Pith reviewed 2026-06-27 10:53 UTC · model grok-4.3
The pith
For every n at least 3 there exist compact sets in R^n whose distance to the convex hull stays fixed under the first n-1 Minkowski self-averages.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
For every n greater than or equal to 3, there exists a compact set A subset R^n such that d(A(k)) equals d(A) greater than zero for every 1 less than or equal to k less than or equal to n minus 1, where d measures Hausdorff distance to the convex hull and A(k) is the k-fold Minkowski average. For every nonempty compact A in R^n with n at least 2, the same distance satisfies d(A(n)) less than or equal to one minus (n minus 1) over n times (2n minus 1) times d(A).
What carries the argument
The k-fold iterated Minkowski average A(k) equals one over k times the sum of k copies of A, used to track invariance of the Hausdorff distance d to the convex hull.
If this is right
- The symmetric Dyn-Farkhi conjecture is false in every dimension n at least 3.
- The threshold k equals n is sharp: the distance is guaranteed to decrease only after n averages.
- The factor 1 minus (n-1) over n(2n-1) supplies an explicit worst-case contraction rate after n averages.
- Repeated Minkowski averaging reduces non-convexity, but the reduction can be delayed by a dimension-dependent number of steps.
Where Pith is reading between the lines
- The same sets may serve as test cases for other convexification operators beyond Minkowski averages.
- The dimensional jump at n equals 3 suggests that symmetric and asymmetric averaging diverge only above a fixed threshold.
- Numerical checks of the contraction constant in dimension 3 would give a direct test of sharpness.
Load-bearing premise
There exists a compact set in R^n for n at least 3 whose distance to its convex hull remains exactly constant under the first n-1 Minkowski self-averages.
What would settle it
An explicit compact set A in some dimension n at least 3 for which d(A(k)) is strictly smaller than d(A) for at least one k less than n, or a compact set in dimension n at least 2 whose d(A(n)) exceeds the stated fractional multiple of d(A).
Figures
read the original abstract
The Dyn-Farkhi conjecture asserts that the square of the Hausdorff distance from a compact set to its convex hull is subadditive with respect to Minkowski addition. The conjecture is elementary in dimension 1, was recently proved by Meyer in dimension 2, and was disproved in dimensions $n\geq3$ by Fradelizi, Madiman, Marsiglietti, and Zvavitch. The symmetric case $A=B$, however, remained open. We show that the conjecture already fails in this restricted setting. More precisely, for every $n\geq3$, we construct a compact set $A\subset\mathbb{R}^n$ such that $$d(A(k))=d(A)>0$$ for every $1\leq k\leq n-1$, where $d(X)$ is the Hausdorff distance from $X$ to its convex hull and $A(k):=\frac1k (A+\dots+A)$ is the $k$-fold iterated Minkowski average of $A$. We also prove that the threshold $k=n$ is sharp: for every nonempty compact $A\subset\mathbb{R}^n$ with $n\geq 2$, we have $$d(A(n))\leq \left(1-\frac{n-1}{n(2n-1)}\right)d(A).$$
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper resolves the symmetric case of the Dyn-Farkhi conjecture by constructing, for every n≥3, a compact set A⊂R^n such that d(A(k))=d(A)>0 for 1≤k≤n-1, where d(X) denotes the Hausdorff distance from X to its convex hull and A(k) is the k-fold Minkowski average. It further proves that this threshold is sharp: for every nonempty compact A⊂R^n (n≥2), d(A(n))≤(1−(n−1)/(n(2n−1)))d(A).
Significance. If the claims hold, the work supplies an explicit geometric counterexample to the symmetric Dyn-Farkhi conjecture in dimensions n≥3 together with a parameter-free upper bound that applies to arbitrary compact sets and demonstrates sharpness of the threshold k=n. The constructive nature of the disproof and the direct, non-circular derivation of the inequality constitute clear strengths.
minor comments (1)
- The abstract states the bound for n≥2 but the construction is given only for n≥3; a brief remark in the introduction clarifying why the bound statement begins at n=2 would improve readability.
Simulated Author's Rebuttal
We thank the referee for their positive evaluation of the manuscript and for recommending acceptance. The report accurately summarizes the main contributions.
Circularity Check
No significant circularity identified
full rationale
The derivation rests on an explicit geometric construction of a compact set A in R^n (n≥3) together with direct verification that d(A(k)) remains equal to d(A) for the first n-1 Minkowski averages, plus a separate parameter-free inequality bounding d(A(n)) that holds for arbitrary nonempty compact sets in Euclidean space. Neither part reduces to a self-definition, a fitted input renamed as prediction, or a load-bearing self-citation chain; the cited prior disproof in higher dimensions is by independent authors and is not invoked to justify the new construction or bound. The argument is therefore self-contained against external geometric benchmarks.
Axiom & Free-Parameter Ledger
axioms (1)
- standard math Standard properties of the Hausdorff metric and Minkowski addition on compact subsets of Euclidean space
Reference graph
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